
heappush (heap, ) if len (heap ) = 0 : print ( "%d Status of items (1 is loaded in backpack, 0 is not loaded in backpack):%s" % (n ,bests ) ) print ( "The best price value is: %d" %bestv ) break #print("heap:") #print(heap) # Upper bound function: calculating the upper bound of value under the current node def maxbound (i ) : global cweightīestv =cvalue +value #print("bestv=%d"%bestv) # The optimal path to store the current optimal valueīests =bests + '0' * (n - len (bests ) ) # In the heap: because python has only a small root heap, the upper bound value is large and the priority is high by inverting the upper bound value if i + 1 =bestv : if i + 1 This code is the branch limit 01 knapsack code under python3 When the right son node satisfies the upper bound constraint, it is added to the subset tree and the priority queue of the nodes.If the left son node is a feasible node, it is added to the subset tree and the priority queue of the nodes The algorithm first checks the feasibility of the left son node of the current extension node. The priority of the node is the sum of the value of the bagged items plus the value of the remaining maximum unit weight of the items filled with the remaining capacity.01 knapsack code#
01 knapsack plus#

Once a node becomes an extension node, all its child nodes are generated at once. In branch and bound method, each active node has only one chance to become an extended node. The problem that items can be partially packed into a backpack is called the backpack problem Branch and boundīranch and bound method often searches the solution space tree of the problem in the way of breadth first or minimum cost (maximum benefit) first. Items cannot be split into smaller units for loading, that is, they cannot be partially loaded.

Note: 01 the knapsack problem requires that an item has only two states of 0 / 1, that is, loading knapsack or not loading knapsack.
01 knapsack how to#
For a given capacity backpack, how to make the items in the backpack have the maximum total value? There are N items, each of which has its own weight and value.
